Can someone please help me I need the answer urgently please

Step-by-step explanation:

AB ≅ BC.  So, ΔABC is an isosceles triangle

Opposite angles of equal sides are equal.

∠BAC = ∠BCA = x°

In ΔABC,

∠ABC + ∠BAC + ∠BCA = 180  {Angle sum property of triangle}

 56 + x + x = 180

56 + 2x = 180

        2x = 180 - 56

         2x = 124

           x = 124/2

           x = 62°

∠BAC = ∠BCA =  62°

∠DCF = ∠BCA   {Vertically opposite angles}

∠DCF = 62°

CDEF is a parallelogram.

In parallelogram, opposite angles are congruent.

∠DEF = ∠DCF

∠DEF = 62°

In a parallelogram, sum of adjacent angles = 180

∠DEF + ∠CDE = 180

62 + ∠CDE = 180

       ∠CDE = 180 - 62

      ∠CDE = 118°

∠CFE = ∠CDE   {In parallelogram, opposite angles are congruent}

∠CFE  = 118°

huh? im pretty sure it is in 199

step-by-step explanation:

answer: translate the circles so they share a common center point and dilate circle y by a scale factor of 3.