ASAP PLEASE help me with this question! This is really urgent! No nonsense answers please.

intuitively, when you take B so far, the lines will have to less "steep" to be tangent to circle so the angle between them will also decrease.

so when you take B closer, increases

not sure if C lies on the line joining B and center, but if it does,

then again you can visualise that when the point is Far, the intersection points are more distant, reducing the angle

and when the point is very close to circle, the tangents $m\angle GCD$ will increase

and at extreme, when B is on the circle, it will become a straight line, and $\angle GCD$ wil become $180^{\circ}$

so it increases when you move closer. hence option 2

square pyramid

step-by-step explanation:

square prism looks like nothing like that

triangular prism has a rectangular base instead of a square base

tetrahedron has a triangular base