Which of the two functions below has the largest maximum y-value? f(x) = -x4- 2
g(x) = -3x3 + 2

Step-by-step explanation:

● f(x) = -x^4 -2

● g(x) = -3x^3 + 2

Derivate both functions:

● f'(x) = -4x^3

● g'(x) = -9x^2

Solve the equations f'(x) =0 and g'(x) =0

● f'(x) = 0

● -4x^3 = 0

● x^3 = 0

● x =0

● g'(x) = 0

● -9x^2 = 0

● x^2 =0

● x = 0

So both functions f and g reach their maximum at 0.

● f(0) = 0^4-2 = -2

● g(0) = -3×0^3 +2 = 2

So g(0)>f(0)

So g has the largest maximum value.

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3

x=-7

step-by-step explanation:

x+3=-10

-10+3=-7

x=-7