hich statement best describes the domain and range of p(x) = 6–x and q(x) = 6x? p(x) and q(x) have the same domain and the same range. p(x) and q(x) have the same domain but different ranges. p(x) and q(x) have different domains but the same range. p(x) and q(x) have different domains and different ranges.

and have the same domain and the same range.

Step-by-step explanation:

and

First of all, let us have a look at the definition of domain and range.

Domain of a function is the set of input value i.e. the value of for which the function is defined.

Range of a function is the set of output value i.e. the value of or for the values of in the domain.

Now, let us consider the given functions one by one:

Let us sketch the graph of given function.

Please find attached graph.

There are no values of for which p(x) is not defined so domain is All real numbers.

So, domain is or

Its range is also All Real Numbers

So, Range is or

Let us sketch the graph of given function.

Please find attached graph.

There are no values of for which is not defined so domain is All real numbers.

So, domain is or

Its range is also All Real Numbers

So, Range is or

Hence, the correct answer is:

and have the same domain and the same range.

y=x+2 hope this jdjxhdnzbdjdo

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°