Quadrilateral ABCD is inscribed in a circle. m∠A is 64°, m∠B is (6x + 4)°, and m∠C is (9x − 1)°. What is m∠D?

m∠D = 97.34°

Step-by-step explanation:

Concept used"

sum of all angles of Quadrilateral is 360 degrees.

If any Quadrilateral is inscribed in circles then sum of opposite angle of that Quadrilateral is 180 degrees

Given

Quadrilateral ABCD is inscribed in a circle

thus,

pair of opposite angles will be

m∠A and m∠C

m∠B and m∠D

thus,

m∠B + m∠D = 180

Thus,

m∠A + m∠C = 180

64+  (9x - 1) = 180

9x = 180 - 63 + 1 = 118

x = 118/9 = 13.11

thus, value of

m∠B is (6x + 4)°

m∠B = (6*13.11 + 4)°  = 82.66°

m∠B + m∠D = 180

82.66 + m∠D = 180

m∠D = 180 - 82.66 = 97.34°

Thus,

m∠D is 97.34°

answer: group b.

step-by-step explanation:

what shape is