Select the correct answer from each drop-down menu. The side length of the square in the figure is 8 cm.

The radius of the inscribed circle is
cm, and the radius of the circumscribed circle is
cm.

Step-by-step explanation:

From the figure, the inscribed circle is the circle inside the square. So, the radius of the inscribed circle is half the side of the square. That is 4 cm.

The circumscribed circle is the circle outside the square and its radius is half the diagonal of the square. Since the square has a side length of 8 cm, the diagonal is computed as follows, using Pythagorean Theorem using half of the square taking the diagonal as the hypotenuse.

d=\sqrt{8^2+8^2}=\sqrt{64+64}=\sqrt{128}d=

8

2

+8

2

​

=

64+64

​

=

128

​

The radius is half the diagonal. So, the radius is

\:r=\frac{\sqrt{128}}{2}=\sqrt{\frac{128}{4}}=\sqrt{32}\:r=

2

128

​

​

=

4

128

​

​

=

32

​

or (32)^(1/2).

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step-by-step explanation:

answer:   28.56 feet (approx)

step-by-step explanation:

since, triangle abc has measure of angle c equal to 55 degrees, measure of angle abc equal to 90 degrees, and length of bc equal to 20 feet.

we have to find out the measurement of segment ab.

therefore, tan 55° =

but bc = 20 feet.

⇒ tan 55 ° =  

⇒ ab = 20 × tan 55 °

⇒ ab = 20 × 1.42814800674

⇒ ab = 28.5629601348   ≈ 28.56 feet