Twice one number added to another number is 18. if the 2nd number is equaled to 12 less than 4 times the 1st number, find the two numbers 2x + y= ? ; y= ?x - ?

8

Step-by-step explanation:

Math Word Problem: Twice one number added to another number is 18. Four times the first number minus the other number is 12. Find the number.?

Let the two numbers be x and y

As per statement twice one number added to another number is 18.

2x + y = 18

y = 18 - 2x…Eq..1

Four times the first number minus the other number is 12.

4x - y = 12…Eq..2

Now substituting the value of y from Eq..1 to Eq..2

4x - y = 12

4x - (18 - 2x) = 12

4x - 18 + 2x = 12

4x + 2x = 12 + 18

6x = 30

x = 30 / 6

x = 5

Thus one number is 5. Now calculating the other number by putting the value of x in Eq. 1

y = 18 - 2x

y = 18 - 2×5

y = 18 - 10

y = 8

Other number is 8

Answer the two numbers are 5 and 8

Let us check the correctness of answer by putting the value of x and y in Eq. 1

y = 18 - 2x

8 = 18 - 2 × 5

8 = 18 - 10

8 = 8

Means answer is correct

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