What is the solution set to the inequality?

Option (2)

Step-by-step explanation:

To find the solution set of the given inequality we will follow the following steps.

1). Convert the inequality into an equation.

2). Find the solutions from the equation.

3). Check these solutions and intervals on a number line.

Given inequality is 5(x - 2)(x + 4) > 0

Step 1. Equation for given inequality is,

          5(x - 2)(x + 4) = 0

Step 2. Solutions for the given equation will be,

           (x - 2) = 0 ⇒ x = 2

           (x + 4) = 0 ⇒ x = -4

Step 3. Therefore, there will be two critical points on the number line,

           x = 2, x = -4

Now we will check the solutions of the given inequality in the given intervals,

x < -4, -4 < x < 2 and x > 2

For x < -4,

Let the solution is x = -5

5(x + 4)(x - 2) = 5(-5 + 4)(-4 - 2)

                     = 30 > 0

Therefore, x < -4 will be the solution area of the inequality.

For -4 < x < 2,

Let the solution is x = 0

5(x + 4)(x - 2) = 5(0 + 4)(0 - 2)

                     = -40 < 0

Therefore, -4 < x < 2 will not be the solution set for the given inequality.

For x > 2,

Let the solution is x = 3

5(x + 4)(x - 2) = 5(3 + 4)(3 - 2)

                     = 35 > 0

Therefore, x > 2 will be the solution area of the inequality.

Summarizing all steps we find that the solution set of the inequality is,

{x | x < -4 Or x > 2}

Option (2) will be the answer.

b is 38 degrees.

a is 52 degrees.

this is because if b is 38 and a is 14 degrees more than b than 38+14=52 and 52+38=90 degrees. hope this .

la parábola es el lugar

geométrico en el cual los puntos tienen una distancia idéntica, equidistantes,

de un punto denominado foco, f, y una recta denominada directriz

el radio vector de una

parábola es el segmento que existe entre un punto cualquiera y el foco.

por la ecuación se observa

que la parábola abre hacia la derecha, por lo cual podemos usar las siguientes fórmulas

la ecuación ordinaria de la

parábola es y^2 = 4px, donde p es la longitud desde el vértice de la parábola al

foco.

la fórmula de la directriz

es x + p = 0

resolviendo:

y^2-9x = 0

y^2 = 9x

4p = 9, entonces p = 9/4

entonces el foco tendrá la

coordenada f(9/4,0)

la directriz vendrá

expresada por

x + p = 0

x = -p

x = -9/4

el problema indica que la

ordenada es igual a 6, entonces

(6)^2=9x

x = 36/9

x = 4

entonces el punto al cual

hay que obtener la distancia será p(4,6)

calculando se tendrá: pf = 

pf = 6,25 u

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step-by-step explanation: