using binomial theorim in how many ways can a campaigner manager assign 15 campaigners to three matatus when 6 are in the first matatu 5 in the second matatu and 4 in the third matatu

The answer is c. 7 (i think) i’m almost sure though

What is the rest of the question?

One shot. if 60% of 10 is 6, then what is 70%? we know it would be seven (since 60% is mathematically 60/100, or 6/10, then 70% is 70/100, or 7/10) but we can check anyway using ratios: 6 : 60% = x : 70%*inverse multiplicationx * 60% = 6 * 70%*divide both sides by 60%x = (6 * 70%) / 60%x = 7and since he has made 6 shots already, he would need just one more to get 7 shots or 70%. if the explanation is too confusing, comment and i will try to