Please someone help me im desperate Find Tan0 , csc0, and cos0 where 0 is the angle shown in the figure. Give EXACT values, not decimal approximations.

1. Tan θ = √11/5

2. Cosec θ = 6√11 /11

3. Cos θ = 5/6

Step-by-step explanation:

Let the side opposite to angle θ be y.

The value of y can be obtained by using the pythagoras theory as follow:

b² = 6² – 5²

b² = 36 – 25

b² = 11

Take the square root of both side.

b = √11

1. Determination of Tan θ

Tan θ =?

Opposite = √11

Adjacent = 5

Tan θ = Opposite /Adjacent

Tan θ = √11/5

2. Determination of Cosec θ.

We'll begin by calculating the Sine θ. This is illustrated below:

Sine θ =?

Opposite = √11

Hypothenus = 6

Sine θ = Opposite /Hypothenus

Sine θ = √11/6

Now, we shall determine Cosec θ as follow:

Cosec θ = 1/Sine θ

Sine θ = √11/6

Cosec θ = 1 ÷ √11/6

Cosec θ = 1 × 6/√11

Cosec θ = 6/√11

Rationalise the denominator

Cosec θ = 6/√11 × √11/√11

Cosec θ = 6√11 /11

3. Determination of Cos θ.

Cos θ =?

Adjacent = 5

Hypothenus = 6

Cos θ = Adjacent / Hypothenus

Cos θ = 5/6

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