The values of the sample mean, sample standard deviation, and (estimated) standard error of the mean are 2.482, 1.614, and 0.295, respectively. Does this data suggest that the true average percentage of organic matter in such soil is something other than 3%

Complete Question

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Yes  the test  suggest that the true average percentage of organic matter in such soil is something other than 3%

Step-by-step explanation:

From the question we are told that

  The  sample mean is  

  The  standard deviation is

   The  standard error is

     The  sample size is

   The  level of significance is  

  The  null hypothesis is

   The  alternative hypothesis is  

Now  the degree of freedom is evaluated as

The test statistics is mathematically evaluated as

The p-value is obtained from the the student t -distribution table , the value is  

The reason for the 2 in the equation is because the test is a two -tailed test i.e  -1.756 and  1.756

Given that the then we fail to reject the null hypothesis

Hence the test the suggest that the true average percentage of organic matter in such soil is something other than 3%

i believe the answer is 68cm

step-by-step explanation:

i just took 34 x 2 because the space between v and y is the same as y to k.

hello :

by applying the distributive property :

6 × 4.3 = 6 × ( 4 + 0.3 )

            =   (6 ×   4) + (6 ×   0.3)

            = 24 + 1.8

6 × 4.3 = 25.8