a. Assume that the selections are made with replacement. Are the events independent? The probability of getting two orders from Restaurant D is . The events (1) independent because choosing the first order (2) the choice of the second order. (Round to four decimal places as needed.) b. Assume that the selections are made without replacement. Are the events independent? The probability of getting two orders from Restaurant D is . The events (3) independent because choosing the first order (4) the choice of the second order.

= a = 0.0206

b = 0.0205.

Step-by-step explanation:

From the question, given that;

Order Accurate         =  328     273    242     142

Order Not Accurate  =  32       54       37       20

Let us make the Total orders given be

T.O = 328+273+242+142+32+54+37+20 = 1128.

a) Let the Prob. that the first order is from restaurant D be

= Number of order from restaurant D / Total number of orders

= 162 / 1128 = 0.1436

Probability of the second order is 0.1436.

This is because, from the question we can tell that the selections are made with replacement, that means the order is the same.

So, the probability of getting 2 orders =

= 0.1436 * 0.1436 = 0.0206

NB: The probability of getting two orders from restaurant B is 0.0206.

This is because choosing the first order does not affect the second order

(independent events).

b) Assuming that the selections are made without replacement , the probability of getting both the orders from restaurant D =

This gives the Total Probability of getting both the orders from restaurant D, without replacement to be =  0.1436*0.1428

= 0.0205.

That is to say choosing the first order affects the second order because of the events are not independent as compared to the first question.

cheers i hope tis helps

the answer is 45 i just did it on oddesy ware