For this item, any answers that are not whole numbers should be entered as a decimal, rounded to the tenths place. In the figure below, line AB, line CD, and line EF intersect at point Q. Line AB is perpendicular to line CD. Complete the following equations. x =
m∠CQF =
m∠AQE =

m<CQF = 32°

m<AQE = 32°

Step-by-step explanation:

m<CQB = m<CQA = 90° (right angle)

m<CQB = m<CQF + m<FQB

m<CQF = 3x + 2

m<FQB = 58°

Therefore,

Solve for x:

m<CQF = 3x + 2

Plug in the value of x to find m<CQF

m<CQF = 3(10) + 2 = 30 + 2

m<CQF = 32°

m<CQF and m<AQE are vertical opposite angles, therefore, they are congruent.

Thus,

m<AQE = 32°

the answer is: d) o, f, and kr.

atomic radius of bromine (br) is 114 pm.

atomic radius of oxygen (o) is 73 pm.

atomic radius of fluorine (f) is 72 pm.

atomic radius of krypron (kr) is 112 pm.

the atomic radius of a chemical element is a measure of the size of its atom.

the atomic radius varies with increasing atomic number, but usually increases because of increasing of number of electrons.

the atomic radius decreases across the periods because an increasing number of protons, because greater attraction between the protons and electrons.

p = 6s

step-by-step explanation: