Given f(x) = x^2 - 2x - 15 find the average rate of change over the interval [0, 5].

Average Rate of Change : 3

Step-by-step explanation:

" Remember that the average rate of change of function f say, on interval [a,b] would be f(b) - f(a) / b - a. Similarly we can solve for the average rate of this function. "

f(5) = x² - 2x - 15 = 5² - 2(5) - 15 = 25 - 10 - 15 = 0,

f(0) = 0² - 2(0) - 15 = 0 - 0 - 15 = - 15

And the average rate of change will be,

f(5) - f(0) / 5 - 0 = 0 - ( - 15 ) / 5 - 0

= 0 + 15 / 5 = 15 / 5 = 3

The average rate of change over the interval [0, 5] is hence 3.

hello from mrbilldoesmath!

answer:

25x^2 + 90x + 84

discussion:

mn(x) = m(n(x)) = m( 5x + 9) =

(5x + 9)^2 + 3 =>

25x^2 + 90x + 9^2 + 3 =

25x^2 + 90x + 84                 (as 9^2 = 9*9 = 81)

which is the second choice

regards,  

mrb

p.s.   i'll be on vacation from friday, dec 22 to jan 2, 2019. have a great new year!

i get you, what you should do is think of the positive things that would come out of it. it will make yours parents proud and raise your grade. you should always try and if you can't focus tell the teacher.