The second and third terms of a G. P is 6 times the fourth term. Find the possible values of the common ratio.

-1/3 or 1/2.

Step-by-step explanation:

Second term = ar, the third = ar^2 and the fourth = ar^3.

So we have the equation:

ar + ar^2 = 6ar^3

r + r^2 = 6r^3

6r^3 - r^2 - r = 0

r(6r^2 - r - 1) = 0

(3r + 1 )(2r -1) = 0

r = -1/3, 1/2.

option a.

step-by-step explanation:

if you look closely at the graph, we can notice that the function is not defined at two different points.

if you look at functions b and c, you will notice that both functions are not defined at just one point. the function b is not defined at x= -5/2 and function c is not defined at x=-5. both options are discarded, given that our function should not be defined at two fiferent points.

now, if you look closely at the graph you will notice that the function sketched is not defined at x=5 and x=-2.