If 3x+2=7(3-x), find the value of 26-x-4

20.1

Step-by-step explanation:

Isolate the variable, x. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS.

First, distribute 7 to all terms within the parenthesis:

7(3 - x) = (7 * 3) + (7 * -x) = 21 + -7x = 21 - 7x

3x + 2 = 21 - 7x

Isolate the variable, x. Subtract 2 and add 7x to both sides:

3x (+7x) + 2 (-2) = 21 (-2) - 7x (+7x)

3x + 7x = 21 - 2

10x = 19

Divide 10 from both sides:

(10x)/10 = (19)/10

x = 19/10 = 1.9

Plug in 1.9 for x in the expression given:

26 - x - 4 = 26 - 1.9 - 4

26 - 1.9 = 24.1

24.1 - 4 = 20.1

20.1 is your value.

~

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.