What are the values of a, b, and c in the quadratic equation –2x2 + 4x – 3 = 0? a = 2, b = 4, c = 3 a = 2, b = 4, c = –3 a = –2, b = 4, c = 3 a = –2, b = 4, c = – 3

Option D is correct answer.

Step-by-step explanation:

Hey, there!

Before finding a,b,c, you remember the formula of quadratic equation,

Where, "a" represents thecoefficient of, x^2 "b" represents the coefficient of y and "c" is a numerical value.

So, the value of a,b,c in this equation "-2x^2+4x-3=0" is:

a= -2

b= 4

and c= -3.

Hope it helps...

answdf

step-by-step explanation: bcuz d is right

geometry: triangles

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call the larger triangle abc

then the smaller triangle cde is similar to abc (all angles are equal, aaa).  

ab is the side that is 36, and we wish to find de, the side corresponding to ab

area_cde = area_abc - area_cde --> area_abc / area_cde = 2

let x=length of de

ratio of areas = (ratio of sides)^2

+2+=+%2836%2fx%29%5e2+

+2+=+1296%2fx%5e2+

++x%5e2+=+1296%2f2+=+648+

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