A prism and two nets are shown below:
3 in
Sin.
94 in
4 in
Prism
Ah
Ab
Net A
Net
Part A: Which is the correct net for the prism? Explain your answer. (2 points)
Part B: Write the measurements of Sides AB, BC, and CD of the correct net. (4 points)
Part C: What is the surface area of the prism? Show your work. (4 points)

Answer/Step-by-step explanation:

Part A: Net A is the correct net. If we decide to fold the net, we'd get the shape of the prism. Folding back net B won't give us the shape of the prism because of the position and arrangement of the right triangular  bases.

Part B:

AB =  3in

BC = 5 in

CD = 9.4 in

Part C: surface area of the prism can be calculated by calculating the area of each part of the net, and summing them together as follows,

Area of the 2 triangular bases = 2(½*base*height of triangle) = 2(½*4*3) = 2*2*3 = 12 in²

Area of the three rectangles =

Surface area of prism = 12 + 112.8 = 124.8 in²

answer: 180

step-by-step explanation:

12-2=10

20-2=18

18x10=180

- "runner b is moving at a slower rate."

- "the graphs shown are graphs of distance(km) against time(min).

the slopes of this graphs are are given by:

slope = (change in y)/(change in x)

= (change in distance)/(change in time)

this is the formula for finding the speed. so, the slope of these graphs represent the speed of the runner.

taking each division in the graph to represent 1 on both axis:

runner a ⇒ speed = (2-0)/(1-0)

= 2/1

= 2 km/min

runner b ⇒ speed = (3-0)/(3-0)

= 3/3

= 1 km/min

this shows that   runner b is moving at a slower rate."