(a) A mixed hockey team of 11 must have at least 5 boys and at least 5 girls. There are 7 boys and 8 girls available for selection. How many different teams can be selected? (b) One of the girls, Caitlin, is selected as captain of the team and must play every game. One of the boys, Stephen, is injured and can no longer play. How many teams can be selected now? Pls answer asap

A) I) 49 teams

II)63 teams

B) 28 teams

Step-by-step explanation:

A) a team of 5 boys and 6 Girls

=7C5+ 8C6

= 21+28

= 49 teams

a team of 6 boys and 5 girls

= 7C6 + 8C5

= 7+56

= 63 teams

B) one girl is kept constant already and a guy has injury

Girls remaining to choose from 7

Boys remaining to choose from 6

= 1 +7C5 + 6C5

= 1+21+6

= 28 teams

hope it

step-by-step explanation:

x^(1/6) · x^(1/6) · x^(1/6)   ·x^(1/6) = x^(4/6)   since we add the exponents

4/6 can be simplified to 2/3

the simplified form is x^(2/3)

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step-by-step explanation:

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