1) Use the Laplace transform to solve the given differential equation subject to the indicated initial conditions. y'' + 6y' + 25y = δ(t − π) + δ(t − 7π), y(0) = 1, y'(0) = 0
2) Use the Laplace transform to solve the given differential equation subject to the indicated initial conditions.
y'' + 6y' = δ(t − 1), y(0) = 0, y'(0) = 1.

-7/8

step-by-step explanation:

instead of subtracting you add the -6/8 and -1/8

hello from mrbilldoesmath!

answer:

(7 x + 6 y) (49 x^2 - 42 x y + 36 y^2)

discussion:

the trick is to recognize that 343 = 7^3 and 216 = 6^3 and, in general,

a^3 + b^3 =   (a + b) (a^2 - a b + b^2).

in our case

343x^3+216y^3   =   (7x)^3 + (6y)^3

so take a = 7x and b = 6y in the above equation to get the answer.

you,

mrb

none of these

step-by-step explanation:

23 + 34 add up to 57 so just inform the teacher of this really stupid mistake

one peck is 9.309 quarts

9.309x 2