) I went from my house to a playground, 300 metres away in 10 minutes. I ran back and
reached in 2 minutes. What was my average
speed? give answer fast!

v = 0.834 m/s or 3 km/h

Step-by-step explanation:

Given that,

Distance between house and playground is 300 meters

If you went 300  metres away in 10 minutes and ran back and  reached in 2 minutes, it means total distance covered by you during whole journey is 300 m + 300 m = 600 m

Total time, t = 10 min + 2 min = 12 min = 720 seconds

Total distance covered divided by total time gives average speed. So,

or

v = 3 km/h

So, the average speed is 0.834 m/s or 3 km/h.

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.