Find the 9th term of the geometric sequence whose common ratio is 23 and whose first term is 3

2.35 x 10^11

Step-by-step explanation:

The formula for finding the nth term in a geometric sequence is ar^n-1.

a = 3, r = 23, and n = 9:

3(23)^9-1 = 3(23)^8 = 2.35 x 10^11.

answer: 2 and 1

step-by-step explanation: got this question

-22

times both sides by 2, times () by 8, add alile terms, move terms, add alike and caculate divide both sides by 3