Let ∠BOC=x+3, ∠AOB=4x−7, and ∠AOC=21. Solve for x.

Step-by-step explanation:

Given  the following angles ∠BOC=x+3, ∠AOB=4x−7, and ∠AOC=21, the expression is true about the angles;

∠AOC = ∠BOC+∠AOB

Substituting the given values into the expression, we will have;

21 = x+3+4x-7

collect the like terms

21 = x+4x+3-7

21 = 5x-4

Add 4 to both sides

21+4 = 5x-4+4

25 = 5x

Divide both sides by 5

5x/5 = 25/5

x = 5

Hence the value of x is 5

f(x) = x^3 -2x^2 -3x

x( x^2 -2x-3)

x( x^2 +x -3x -3)

x( x(x+1) -3(x+1))

x( x-3)( x+1)

so zeroes are 0, 3,-1

its (2) option