Katie walks 2 ft forward and 5 ft backwards. Find her displacement traveled.

Step-by-step explanation:

It is given that, Katie walks 2 ft forward and 5 ft backwards. We need to find her displacement traveled.

The difference between final position and the initial position is equal to displacement. It is the shorted path covered.

Let forward is +x and backward is -x

Initial position of Katie = +2 ft

Final position of Katie = -5 ft

Displacement = final position - initial position

= -5 - 2

Displacement = -7 ft

So, her displacement is 7 feet in backward direction.

is this part of a question or something