Let y = (2 6) and u = (7 1). Write y as the sum of a vector in Span(u) and a vector orthogonal to .

The question is missing. Here is the complete question.

Let y = and u = . Write y as the sum of a vector in Span(u) and a vector orthogonal to u.

y =

Step-by-step explanation: The sum of vectors is given by

y =   + z

where   is in Span(u);

vector z is orthogonal to it;

First you have to compute the orthogonal projection of y:

= proj y =

Calculating orthogonal projection:

. =

. =

Calculating vector z:

z = y -

z =

z =

Writing y as the sum:

85.560%

step-by-step explanation:

conditional probability is defined as:

p(a|b) = p(a∩b) / p(b)

in other words, the probability that a occurs, given that b has occurred = the probability that both a and b occur / the probability that b occurs.

in this example:

p(turns 64 | turns 44) = p(turns 64 & turns 44) / p(turns 44).

if someone turns 64, they must have already turned 44, so:

p(turns 64 | turns 44) = p(turns 64) / p(turns 44)

on page 42, we see that of the original 100,000, 94944 turn 44, and 81234 turn 64.   therefore:

p(turns 64 | turns 44) = 81234 / 94944

p(turns 64 | turns 44) = 0.85560

180-142=38 for the acute angle next to the entry

90+38=128

180-128=52

a=52

step-by-step explanation: