write in point slope form, slope intercept form, and standard form an equation that passes through (-1,2) with slope 4

see below

Step-by-step explanation:

Point slope form is

y-y1 = m(x-x1) where m is the slope and (x1,y1) is a point on the line

y - 2 = 4(x- -1)

y - 2 = 4(x+1)

slope intercept form

y = mx+b where m is the slope and b is the y intercept

y = 4x+b

Substituting the point in

2 = 4(-1)+b

2 = -4+b

6 =b

y = 4x+6

standard form

Ax +by = c  where A is a positive integer and b and c are integers

y = 4x+6

Subtract 4x from each side

-4x+y = 6

Multiply by -1

4x -y = 6

the forst and 3rd

step-by-step explanation:

p ÷ r = tan(x)

step-by-step explanation:

given that there is a figure below shows a right triangle: a right triangle is shown with hypotenuse equal to q units and the length of the legs equal to p units and r units.

graph is missing so i will create the graph as per given information.

the angle between the legs having lengths p units and q units is y degrees. the angle between the legs having lengths r units and q units is x degrees.

now we need to find about what is p ÷ r equal to.

so we can use trigonometric ratio tan(x)=[altitude]/[base] to find the value of p ÷ r, because p is the altitude and r is the base.

p ÷ r=tan(x)

hence final answer is p ÷ r=tan(x).