Zack wants his rectangular garden to be 8 feet longer than it is wide and for its area to be less than or equal to 660 ft2. What are the possible values for the length of his garden in feet (x)?

L≤30ft

Step-by-step explanation:

The area of the garden A = Length(L)*Width(W)

If Zack wants his rectangular garden to be 8 feet longer than it is wide, then

L = 8+W

Also, if he wants the area to be less than or equal to 660 ft², the A ≤ 660

LW≤660 1

(8+W)W ≤ 660

W²+8W-660≤0

W²+30W-22W-660≤0

W(W+30)-22(W+30)≤0

(W-22)(W+30)≤0

W-22≤0

W≤22 (neglecting the positive value)

Substituting W = 22 into equation 1

22L≤660

L≤660/22

L≤30

Hence the possible values for the length of his garden in feet are values less than and equal to 30 feet.

-14 is the answer

hope this : ))

the polynomial is a perfect square trinomial of the form a^2-2ab+b^2:

option a. true

step-by-step explanation:

9x^2-12x+4

comparing with the form a^2-2ab+b^2

1.) a^2=9x^2

solving for a: square root both sides of the equation:

sqrt(a^2)=sqrt(9x^2)

a=sqrt(9) sqrt(x^2)

a=3x

2.) b^2=4

solving for b: square root both sides of the equation:

sqrt(b^2)=sqrt(4)

b=2

to be a perfet square trinomial 2ab must be equal to 12x. let's check:

2ab = 2 (3x) (2)

2ab = 12x

correct