Please answer ASAP, the first person with a good explanation and the right answer will be marked brainiest. Please help. In triangle $ABC,$ angle bisectors $\overline{AD}$ and $\overline{BE}$ meet at point $I.$ Prove that \[\angle DIB = 90^\circ - \frac{\angle BCA}{2}.\] (In triangle ABC, angle bisectors AD and BE meet at point I. Prove that angle DIB = 90-BCA/2.)

Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the correct position in the answer box. release your mouse button when the item is place. if you change your mind, drag the item to the trashcan. click the trashcan to clear all your answers. using the technique in the model above, find the missing segments in this 30°-60°-90° right triangle. ab = 8 bc = 4 cd =

Solve this riddle: i am an odd number. i an less than 100. the some of my digit is 12. i am a multiple of 15. what number am i?

Maria solved an equation as shown below. what is the solution to maria’s equation?