Solve for y
4x + 7y +5

To find the slope, m, of the line represented algebraically by the given linear equation in two variables: 4x = 7y + 5, first put the given equation in the slope-intercept form of the equation of a straight line, i.e., y = mx + b, as follows:

4x = 7y + 5 (Given)

4x - 5 = 7y + 5 - 5

4x - 5 = 7y + 0

4x - 5 = 7y

7y = 4x - 5 since equality is symmetric, i.e., if a = b, then b = a.

(7y)/7 = (4x - 5)/7

(7/7)y = (4x)/7 - 5/7

(1)y = (4/7)x- 5/7

y = (4/7)x - 5/7

From the last step above, the given equation is now in the slope-intercept form of the equation of a straight line: y = mx + b, i.e., y = (4/7)x - 5/7; therefore, we can now see by observation, that the slope of the line is m = 4/7 which means that the line has a positive slope, i.e., it's > 0, which means that if the line were to be constructed on a Cartesian coordinate system, it would slope upward from left to right and would intersect the y-axis at the point (0, -5/7).

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