Show that the statement is true. If DF has endpoints D(-1,8) and E(3,-2), then the midpoint M of DE lies I
in Quadrant I.
The midpoint M is
and the y-coordinate is (select)
). M lies in (select)
since the x-coordinate is (select) v

it has to have an angle of 90 degrees

no oblique asymptote

step-by-step explanation:

to find the oblique asymptote of f(x)

here numerator has degree 1 and denomintor degree 2

degree of numerator < degree of denominator

hence there is no oblique asymptote

when the degree of the denominator > that of the numerator, we saw that the value in the denominator got so much bigger, so quickly,   giving us a horizontal asymptote of the x-axis. or we can write

f(x) = a polynomial of x + a proper fraction.

in this case only we have oblique asymptotes but not when numerator has less degree.

you can use a^2+ b^2=c^2