How many pennies could you have if: When you break the pennies into groups of 2, you have
1 penny left over, AND when you break the pennies into
groups of 3, you have 1 penny left over, AND when you
break the pennies into groups of 5, you have 1 penny
left over, AND when you break the pennies into groups
of 7, you have NO pennies left over?

The number of pennies are 91 pennies

Step-by-step explanation:

The given parameters are

When we split the pennies in twos the number left = 1

When the pennies are split in 3s the number left = 1

When the pennies are split in 5s the number left = 1

When the pennies are split in 7 the number left = 0

Therefore, 7 is a factor of the number

Given that when the pennies are split in 5s the number left = 1, the number ends with a 1

We have the products of 7 ending with 1 from Excel as 21 and 91, 161...

We check 91 given 21 is directly divisible by 3 as follows;

91/2 = 45 remainder 1

91/3 = 30 remainder 1

91/5 = 18 remainder 1

91/7 = 13 remainder 0

Therefore, the number of pennies are 91 pennies.

answer:   (s+1)(s+4)

step-by-step explanation:

factor s2+5s+4

s2+5s+4

=(s+1)(s+4)