Set G is the set of positive integers divisible by 4 and Set F is the set of perfect squares. List the first 5 elements of set H, which contains numbers in G that are
also elements of F.

Greetings from Brasil...

G = {4; 8; 12; 16; 20; 24; 28; 32; 36; 40; 44; 48; 52; 56; 60; 64; 68; 72; 76; 80; 84; 88; 92; 96; 100; 104; ...}

F = {1; 4; 9; 16; 25; 36; 49; 64; 81; 100; ...}

So, according to the statement, it is desired:

G ∩ F - the intersection between the 2 sets, that is, which numbers are present simultaneously in the 2 sets

Looking at the sets we conclude that

OBS: note that in truth G are the multiples of 4

answer:   (s+1)(s+4)

step-by-step explanation:

factor s2+5s+4

s2+5s+4

=(s+1)(s+4)

believe it or not anna is correct good job anna give me a fist bump there u go gal