5. John and Mary are taking a math course. The course has only 3 grades: A, B, and C. The probability that John gets a B is 0.3 .The probability that Mary gets a B is 0.4 . The probability that neither gets an A but at least one gets a B is 0.1 .What is the probability that at least one gets a B but neither gets a C

0.6

Step-by-step explanation:

In the question, we are told that:

The probability that John gets a B is 0.3 .

The probability that Mary gets a B is 0.4 .

The probability that neither gets an A but at least one gets a B is 0.1

The probability that at least one gets a B but neither gets a C

=( The probability that John gets a B ) +( The probability that Mary gets a B )- (The probability that neither gets an A but at least one gets a B is 0.1

= 0.3 + 0.4 - 0.1

= 0.7 - 0.1

= 0.6

Therefore, the probability that at least one gets a B but neither gets a C is 0.6

d. 24+-0.114

step-by-step explanation:

the question requires us to calculate the approximate 95% confidence interval for the mean number of ounces of ketchup per bottle in the sample given the following statistics;

sample mean = 24

standard deviation, σ = 0.4

sample size , n = 49

the confidence interval for a population mean is calculated using the formula;

sample mean ± z-score*(σ/sqrt(n))

the z-score associated with a 95% confidence interval, from the standard normal tables, is;

1.96

substituting these values into the formula;

24 ± 1.96*(0.4/7)

= 24 ± 0.112

from the alternatives given, choice d is closest to the above expression;

okay..i will pick 8!