In 2011, a U. S. Census report determined that 68% of college students are working students. A researcher thinks this percentage has changed and surveys 144 college students. The researcher reports that 93 of the 144 are working students. Is there evidence to support the researcher's claim at the 1% significance level

We will fail to reject the null hypothesis and conclude that there is sufficient evidence not to support the researchers claim.

Step-by-step explanation:

We are given;

Population proportion; p = 68% = 0.68

Sample proportion; p^ = 93/144 = 0.6548

n = 144

The hypotheses are:

Null hypothesis;H0: p = 0.68

Alternative hypothesis;Ha: p ≠ 0.68

np = 144 × 0.6548 > 5 and nq = n(1 - p) = 144(1 - 0.68) > 5.

Since np and nq are more than 5, we can use the z-test .

z-formula in this case is;

z = (p^ - p)/√(p(1 - p))

Plugging in the relevant values, we have;

z = (0.6548 - 0.68)/√(0.68(1 - 0.6548))

z = -0.0252/0.4845

z = -0.052

From the z-table attached, we have a p-value of approximately 0.4801

P-value is higher than the significance level of 0.01.

Thus,we will fail to reject the null hypothesis and conclude that there is no sufficient evidence to support the researchers claim.

(- 1, 0 )

step-by-step explanation:

an x- intercept is where the function crosses the x- axis.

to find the x- intercept/s look for the value of x when f(x) = 0

from the given table there are 3 values of x where f(x) = 0

when x = - 1, x = 2, x = 3

the one that is listed is (- 1, 0 )

in the attachment.   i didn't see your choices.   the word which means there is choices.

step-by-step explanation:

(x,y)

x tells you how much left or right you go from the origin

y tells you how much down or up you go from the origin

so for example (-3,2), you go left 3 and up twice. i denoted which of the ordered pairs is which in my graph.