Manori’s bag has 10cent and 20cent coins. She has 202 coins with a total value of $31.90. How many 20cent coins does manori have?

a = 85 10cent coins

b = 117 20cent coins

Step-by-step explanation:

a = 10c coins

b = 20c coins

$31.90 = c3190

a + b = 202 => a = 202 - b

10a + 20b = 3190

10(202 - b) + 20b = 3190

2020 - 10b + 20b = 3190

10b = 3190 - 2020

10b = 1170

b = 117 (20cent coins)

a = 202 - 117

= 85 (10cent coins)

Let the number of 10 cent coins be x
Number of 20 cent coins = y
$31.90 = 3190 cents

x + y = 202
x = 202 - y

10(202-y) + 20y = 3190
2020 - 10y + 20y = 3190
2020 + 10y = 3190
10y = 3190 - 2020
10y = 1170
y = 117

Number of 20 cent coins = 117

Now to find the value of x

x + y = 202
x + 117 = 202
x = 202-117
x = 85

Number of 10 cent coins = 85

VERIFY:

10(85) + 20(117) = 3190
850 + 2340 = 3190
3190 = 3190
LHS = RHS
Hence, verified

Hope it helps
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