The sum of twice a number and another number is 24. The difference of twice the first number and the other number is 12. Which system would model this situation, and what is the solution?
A 2(x + y) = 24
2(x - y) = 12
Solution: (96)
B. 2x + y = 24
2x - y = 12
Solution: (96)
C. 2(x + y) = 24
2x - y = 12
Solution: (6,9)
D. 2x + y = 24
2(x - y) = 12
Solution: (6,9)
Please hurry !

B

Step-by-step explanation:

Let first number = x

Second number = y

Twice a number = 2*x = 2x

The sum of twice a number and another number is 24

2x + y  = 24    (I)

The difference of twice the first number and the  other number is 12.

2x - y = 12 (II)

Add equation (I) & (II)  and y will be eliminated and we can find the number 'x'

(I)       2x + y = 24

(II)      2x - y  = 12   {Now add the two equations}

          4x      = 36

Divide both sides by 4

4x/4 = 36/4

x = 9

Plug in the value of 'x' in equation (I)

2*9 + y = 24

 18 + y = 24

Subtract 18 from both sides

18 + y - 18 = 24 - 18

       y = 6

The numbers are 9, 6

n

step-by-step explanation:

the equation for this situation is y=122+45. to solve the equation you would add 45 and 122 to get a total of 167lbs. in conclusion, grace's weight eight weeks ago was 167lbs.