50 Points, thanks for the help :) Each question is related to the first question. I don't get this stuff fsr
（＞人＜；）

See bolded for each part below.

Step-by-step explanation:

Attachment 1. (a) The range is 400 dollars, as her greatest balance was 400 dollars, so her domain would be 3 weeks.

( b ) Remember that B(0) models the balance over the course of 0 days. As you can see that starting mark is about half of the greatest balance on the graph, 400 dollars. Therefore you can estimate B(0) to be $200.  

(c) B(12) models the balance over the course of 12 days. It mentions that at B(12) the balance reaches $0, so in function notation that would be B(12) = 0.

(d) Segment 4 would represent that information. As you can see on the graph, the only time period with which the balance became 0 is represented by the fourth segment.

Attachment 2. (a) As you can see on the graph, Ebony reached $400 on day 4, and stayed as such throughout day 8 (modeled by line segment 2). Therefore B(5) = 400 = B(6) = B(7).

(b) We also know that B(0) = ( About ) 200, B(4) = 400. Therefore B(1) = 250, B(2) = 300, B(3) = 350. The slope changes by a rate of 50.

(c) Jade is incorrect. By looking at the graph you can see that the rate from day 8 to day 12 is greater than the rate from day 0 to day 4.

Attachment 3. (a) I would say the amounts she deposited were less than $100 per day. Remember that from day 0 to 4 the slope is about 50. The slope of the line segment that models this situation, line segment 6, has about the same slope, 50.

(b) On day 21 she had 300 dollars, as it seems that this marking is between the starting amount (200) and 400. There are 5 days between 16 and 21. On day 16 she deposited 100 dollars. From then on she apparently deposited 50 dollars,

100 + 50 * 4 = 100 + 200 = 300 ✓

a - base

b - exponent

so,

answer:

step-by-step explanation:

here, the total dishes = 10

dishes having meat = 3 ( chicken, meatloaf and hamburger )

thus, the probability of having meat on the chosen dishes = number of dishes having meat / total dishes

=

therefore, the probability of not having meat = 1- the probability of having meat on the chosen dishes

=

=

=

⇒ option b is correct.