Question 13 A train runs 68m, 127m, 208m, 312m, and 535m in five successive minutes after it
starts. For the next five minutes, it runs an average speed of 33 km/h. Find the
total distance covered in ten minutes,
A. 12 km
B. 10 km
C. 4 km
D. none

C

Step-by-step explanation:

Here in this question , we are interested in calculating the total distance covered by the train in the 10 minutes that it ran.

From the first part of the question, we already know the distances in the first 5 minutes.

Now, to calculate the total distance in the second 5 minutes, we use the distance formula since we have the average speed and the time;

Mathematically; Total distance = average speed * time

From the question, average speed is 33km/h, while time is 5 minutes. To achieve a consistent unit, we convert 5 minutes to hours.

That would be 5/60 = 1/12 hours

So the total distance in the second 5 minutes is;

33 * 1/12 = 2.75 km

Now, to calculate the total distance traveled, let’s add up the distances in the first 5 minutes and convert to kilometers;

That would be;

68 + 127 + 208 + 312 + 535 = 1,250 m

Let’s convert this to km.

We simply divide by 1000 = 1250/1000 = 1.25 km

The total distance is thus ;

1.25 + 2.75 = 4 km

d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

now, we can cross multiply

and we get

so, this could be step to prove it

5

step-by-step explanation: