Mathematics, 22.08.2020 04:01 ciel8809
Given IQ scores are approximately normally distributed with a mean of 100 and standard deviation of 15, the proportion of people with IQs above 130 is:
Answers: 2
![P(X130)=P(\dfrac{X-mean}{ standard\ deviation}\dfrac{130-100}{15})\\\\= P(Z2)\ \ \ \[Z=\dfrac{X-mean}{ standard\ deviation}]](/tpl/images/0727/0639/ef51a.png)
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