1. Find the least common multiple of the denominators for the following equations. 1 1 5 1
3 6 2
a. -X+-=---X
5
3 12
b. -9+x=-X-
3
با بیا
5 2 4 1
c. -X-
X +
9 3 5 9
1
1
1 2
d. -x +
=-+
7. 6 4

i can't read the graph

step-by-step explanation:

you can first factor out the n to get n(1+5). we know that 1+5 is 6, so we just have 6n.

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116

= 5

step-by-step explanation:

to find the 15th term substitute n = 15 into the nth term formula

= (- 3 × 15 ) + 50 = - 45 + 50 = 5