Two positive consecutive numbers are represented by x and x+1. If four is added to the first number and two is subtracted from the second number, the quotient of the new numbers is 11/16
Determine the numbers algebraically.

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x =first number

x+1 = second number

(x) + 4 = x + 4 = 1 ^ new number [first number + 4]

(x + 1) -2 = x - 1 = 2 ^ new number [second number - 2]

now, we resolve it:

we eliminate the denominator and do c.e.: 16x - 16 ≠ 0; 16x ≠ 16; x ≠ 1

5x + 75 = 0

x = - 15

so x + 1 = - 14

But what you ask are two positive numbers! Are you sure that you write correctly the question? Thank you

i = 2 / - 5

step-by-step explanation:

evaluation of ( 2 - 4 ) ( p + q ) when p = 2 and q = 5 i, by putting values of p and q,                                                                    

use the power rule  

( a b ) n = a n b n

to distribute the exponent.

apply the product rule to  

3 x 2 y 3 . ( 3 x 2 ) 2 ( y 3 ) 2

apply the product rule to  

3 x 2 . 3 2 ( x 2 ) 2 ( y 3 ) 2

raise  

3

to the power of  

2 . 9 ( x 2 ) 2 ( y 3 ) 2 multiply the exponents in   ( x 2 ) 2

.

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 2 ⋅ 2 ( y 3 ) 2

multiply  

2   by   2 . 9 x 4 ( y 3 ) 2

multiply the exponents in  

( y 3 ) 2 .

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 4 y 3

⋅

2

multiply  

3   by   2 . 9 x 4 y 6

step-by-step explanation: