A ball is thrown straight up in the air such that its velocity after t seconds is given by v (t) = -32t + 128 feet per seconds. When does it reach the maximum height from ground?
1 second
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Question 11
6 pts
With the setup of previous question, answer the following: if the ball was thrown from the terrace of
a 64 feet tall building, height of the ball after t seconds is given by h (t) = at2 + bt + c, where a=
[Select ]
ş, b= [Select]
,C=
Select

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

step-by-step explanation:

cats

6,250

step-by-step explanation:

to get the area, multiply 360 by 160.(57,600)

to find out how many bags of fertilizer it will take, first figure out how many square feet one bag can hold. divide 1000 by 8(125) to get the unit rate(how many square feet one pound of fertilizer can hold)and multiply it by 50(6250). if i haven't made a mistake, that is the answer.

idk

step-by-step explanation: