Question 2 (1 point) According to Hooke's Law, the force needed to stretch a spring varies directly to the amount the spring is stretched 150 pounds of force
stretches a spring five inches, how much will the spring be stretched by a force of 180 pounds?
inches
Blank 1:

Explanation:

x = amount (in inches) the spring is stretched

y = force applied (in pounds)

y = kx for some constant k, since x and y vary directly

Plug in the given info that x = 5 and y = 150 pair up together

Solve for k

150 = k*5

150/5 = k

k = 30

The equation goes from y = kx to y = 30x. Whatever the stretching distance (x) is, you multiply by 30 to get the force needed (y) to pull the spring.

Plug in y = 180 to solve for x

y = 30x

180 = 30x

30x = 180

x = 180/30

x = 6

The spring will be stretched 6 inches if you apply a force of 180 pounds.

the range is 19

step-by-step explanation:

the range is biggest number minus the smallest, so in this case it would be

41 - 22 = 19