Given f(x)=x2−2x−2, completing the square to solve for the function's zeros yields which of the following? A. (x−1)2=−2 B. (x−2)2=4 C. (x−2)2=2 D. (x−1)2=3

(x-1)² = 3

Step-by-step explanation:

Given f(x)=x²−2x−2

Completing x²−2x−2 = 0 to square

Correct choice is D

answer: 2 and 1

step-by-step explanation: got this question

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.