Three sphere of radius 4cm each fit inside a tube calculate the percentage of the tube.

66.6% (see below)

Step-by-step explanation:

Each sphere 4/3r²=4/3(4²)=268.08cm³

Assuming the tube is the same width and height as the three spheres,

V=r²h=(4²)24=1206.37

The three spheres are 268.08*3=804.24cm³

The tube is 1206.37cm³

I’m not sure if your question is asking the percentage of the tube that’s filled, or the percentage that’s unfilled.

Filled: 804.24÷1206.37=0.66666=66.6%

Unfilled: 1206.37-804.24=402.13

402.13÷106.37=0.33333=33.3%