A 50 litre solution of acid and water contains 10 litres of acid. How much water must be added to make the solution 8 % acidic. Will mark brainest to whoever answers.

Step-by-step explanation:

Acid present in the solution = 10 L

Required volume concentration of acid = 8/100

Let x amount of water be added to achieve the required %.

In the new solution, proportion of acid= 10/(50+x)

Therefore,

10/(50+x) = 8/100

x=75

Ans: 75 L of water must be added to the solution

b is the final answer! : )