The sum of 6consecutive integers is 519. What is the third number in this sequence?

The third sequence Integer is 86.

SOLUTION:-

Given:

The sum of 6 consecutive integers is 519.

To find:

The third number in sequence.

Explanation:

Let the first integer be R.

&

6 consecutive Integer is;

R, R+1,R+2,R+3,R+4,R+5

According to the question:

=) R + R+1+R+2+R+3+R+4+R+5= 519

=) 6R + 15 = 519

=) 6R = 519 -15

=) 6R = 504

=) R= 504/6

=) R= 84

Therefore,

Sequence Integer:

1st number is R= 84.

2nd number is R+1= 84 +1 = 85.

3rd number is R+2 = 84 +2 = 86.

4th number is R+3 = 84 +3 = 87.

5th number is R+4 = 84 +4 = 88.

6th number is R+5 = 84 +5 = 89.

Hope this helped.

v = 1/3 a^2h

step-by-step explanation:

the volume is 1/3 a^2h.

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v