Uhm, yeah im not very good at math, i need to graduate man, someone help lol

d=√73=8.544

Step-by-step explanation:

Find distance (d) between market (0,8) , court house(6,5) and library(6,-1)

d between two pint is :

d=√(x2-x1)²-(y2-y1)²

d between market and court house:

d=√(6-0)²+(5-8)²

d=√36+9=√45 = 6.7082 ≅6.71 rounded to the nearest hundredths

d between courthouse and the library:

d=√(6-6)²+(-1-5)²

d=√36=6

the distance that Runner A ran=6.71+6=12.71

the distance from the library to the school:

d=√(6-(-2))²+(-1-(-4))²

d=√8²+3²

d=√64+9

d=√73=8.544 ( rounded to the nearest hundredth)

Runner B went  8.544 further than Runner A before stopping at school ( which is the distance between the library and the school.

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!

-7/8

step-by-step explanation:

instead of subtracting you add the -6/8 and -1/8