The quadratic function g(x) has a vertex at (-5, 0) and y-intercept of (0, -5). What is g(1)?

A quadratic function has a degree of 2, and it is represented as: . The value of g(1) is -7.2

Given that:

--- the vertex

--- the y-intercept

The quadratic function in vertex form is:

Where:

--- the vertex

So, we have:

Substitute to calculate the value of a

Divide both sides by 25

So, the quadratic equation is:

Rewrite as a function

To calculate g(1), we simply substitute 1 for x

Hence:

The value of g(1) is -7.2

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g(1)=7 1/5

Step-by-step explanation:

vertex (-5,0) , y intercept(0,5)

the quadratic equation is in the form of a parabola: y=ax²+bx+c

y=a(x-h)²+k    find a and b and c

5=a(0-(-5))²+0

5=a(5)²+0

5=25a  ⇒ a=5/25 ⇒ a=1/5

-b/2a=h

-b=2ah ⇒=-b=2(1/5)(-5) ⇒ -b=-2⇒ b=2

y=c=5 ( when x=0, y intercept)

y=1/5x² + 2x + 5

g(1)=1/5(1)²+2(1)+5

g(1)=1/5+2+5

g(1)=7 1/5

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step-by-step explanation: