What’s the Answer
please?

Widths are 2, 4, 5

Border or the perimeter of all these rectangles = 16

Perimeter of a rectangle

=> 2 ( L + W)

W = Width

L = Length

Area of a rectangle

=> L x W

First rectangle

Perimeter =  2(L+W)

=> 2 (L + 2) = 16

=> 2L + 4 = 16

=> 2L + 4 - 4 = 16 - 4

=> 2L = 12

=> 2L/2 = 12/2

=> L = 6

Length of the First Rectangle = 6

Area = L x W

=> 6 x 2 = 12

Area of the First Rectangle = 12

Second rectangle

Perimeter =  2( L + W)

=> 2 (L + 4) = 16

=> 2L + 8 = 16

=> 2L + 8 - 8 = 16 - 8

=> 2L = 8

=> 2L/2 = 8/4

=> L = 4

Length of the Second Rectangle = 4

Area = L x W

=> 4 x 4

=> 16

Area of the Second Rectangle = 16

Third Rectangle

Perimeter = 2 (L + W)

=> 2 (L + 5) = 16

=> 2L + 10 = 16

=> 2L + 10 - 10 = 16 - 10

=> 2L = 6

=> 2L / 2 = 6/2

=> L = 3

Length of the Third Rectangle = 3

Area = L x W

=> 3 x 5

=> 15

Area of the Third Rectangle = 15

To find which figure covers more spaces, we need to which figure has more area.

=> Rectangle 2 has the largest area = 16

its 4 because 2 times 2 is 4, if you double the number two you get four

option (b) is correct

step-by-step explanation:

to find the solution of this system, we need to convert it into reduced row-echelon form. we have,

after applying row operations r2 -> r2/2 and r3 -> r3/3, we get,